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2x^2+21x+7=0
a = 2; b = 21; c = +7;
Δ = b2-4ac
Δ = 212-4·2·7
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{385}}{2*2}=\frac{-21-\sqrt{385}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{385}}{2*2}=\frac{-21+\sqrt{385}}{4} $
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